Microsoft.Net Developer

Partial View with Layout in MVC

We can use partial view with layout page. Here is the sample code...

Model

public class Menu
{
 public string MenuText { get; set; }
 public string MenuUrl { get; set; }
 public string ToolTip { get; set; }
}

Controller

I have created a common controller and HeaderMenu action to use server side code.

public ActionResult HeaderMenu()
{
 List<Menu> menu = new List<Menu>
 {
  new Menu(){ MenuText = "About", MenuUrl = "/Home/About", ToolTip = "About us"},
  new Menu(){ MenuText = "Contact", MenuUrl = "/Home/Contact", ToolTip= "Contact us"},
  new Menu(){ MenuText = "Products", MenuUrl = "/Products", ToolTip= "Product Catalog"}
 };

 return PartialView(menu);
}

View

To use "HeaderMenu" partial view in Shared folder in Views. Change the Html code as per your design.

<div class="navbar navbar-inverse navbar-fixed-top">
    <div class="container">
        <div class="navbar-header">
            <button type="button" class="navbar-toggle" data-toggle="collapse" data-target=".navbar-collapse">
                <span class="icon-bar"></span>
                <span class="icon-bar"></span>
                <span class="icon-bar"></span>
            </button>
            @Html.ActionLink("Application name", "Index", "Home", new { area = "" }, new { @class = "navbar-brand" })
        </div>
        <div class="navbar-collapse collapse">
            <ul class="nav navbar-nav"> 
                @if (Model != null)
                {
                    foreach (var item in Model)
                    {
                        <li><a href="@item.MenuUrl" title="@item.ToolTip">@item.MenuText</a></li>
                    }
                }
            </ul>
        </div>
    </div>
</div>

Layout page

Finally I called partial view in layout page as below

<body>
     @Html.Action("HeaderMenu", "Common")
    <div class="container body-content">
        @RenderBody()
        <hr />
        <footer>
            <p>&copy; @DateTime.Now.Year - My ASP.NET Application</p>
        </footer>
    </div> 
</body>

Output

Hope this will help you and save your time.

Enjoy !!!

The underlying connection was closed: Could not establish trust relationship for the SSL/TLS secure channel.

System.Net.WebException: The underlying connection was closed: Could not establish trust relationship for the SSL/TLS secure channel.

I got below error while calling web api on https and found the solution.

Error

System.Net.WebException: The underlying connection was closed: Could not establish trust relationship for the SSL/TLS secure channel.

Solution

I solved this error by adding this line before calling the web method:

System.Net.ServicePointManager.ServerCertificateValidationCallback = (senderX, certificate, chain, sslPolicyErrors) => { return true; };

Hope this will help you and save your time.

Enjoy !!!

IQueryable - Value cannot be null. Parameter name: property

Value cannot be null.

Parameter name: property

I got below error while I called orderby with IQueryable,

Error

Value cannot be null.
Parameter name: property

StackTrace:
.... OrderBy[T](IQueryable`1 query, String memberName, String direction) ....

I searched on many sites but did not get solution, then I start trial and run method on code. Finally I found that it was my silly mistake,

Solution

SQL column name and what you passing in code should be same, its case sensitive

I was passing : countryName

SQL Column name: CountryName

Hope this will help you and save your time.

Enjoy !!!

Create and Publish own nuget package

First create class library project, here I have created "DemoApp" project.

Generate the initial manifest

Open a command prompt and navigate to the project folder containing DemoApp.csproj file.

Run the following command: 

nuget spec DemoApp.csproj

By specifying a project, NuGet creates a manifest that matches the name of the project, in this case DemoApp.nuspec. It also include replacement tokens in the manifest.

Open DemoApp.nuspec in a text editor to examine its contents and udpate

Create Package

From a command prompt in the folder containing your .nuspec file, run the command 

nuget pack

NuGet generates a .nupkg file in the form of identifier-version.nupkg, which you'll find in the current folder.

Publish with nuget push

nuget push DemoApp.1.0.0.nupkg APIKey-GetFrom-Nuget-Account -Source https://api.nuget.org/v3/index.json

Hope this will help you and save your time.

Enjoy !!!

HTTP Error 500.19 - Internal Server Error

The requested page cannot be accessed because the related configuration data for the page is invalid.

Solution:

Please check if there is any url rewriting tag is there in web.config file, if exists then remove it.

Hope this will help you and save your time.

Enjoy !!!

Get Time Zone list in C#

Here, it is a sample code to get time zone list in C#

string listTimeZone="";

foreach (TimeZoneInfo tzi in TimeZoneInfo.GetSystemTimeZones())
 listTimeZone += tzi.Id + " - " + tzi.DisplayName;

protected void Page_Load(object sender, EventArgs e)
        {
            var inputTime = Convert.ToDateTime("01/15/2019 04:30:00").ToUniversalTime();
 
            TimeZone localZone = TimeZone.CurrentTimeZone;

            lblMessage.Text = localZone.StandardName;

            DateTime outPutTime = inputTime.ToTimeZoneTime(localZone.StandardName);

            lblMessage.Text += "<br>" + inputTime.ToString();
            lblMessage.Text += "<br>India = " + outPutTime.ToString();


            lblMessage.Text += "<br>US Eastern Standard Time = " + inputTime.ToTimeZoneTime("US Eastern Standard Time").ToString();

        }

public static class genericDate
    {
        public static DateTime ToTimeZoneTime(this DateTime time, string timeZoneId = "Pacific Standard Time")
        {
            TimeZoneInfo tzi = TimeZoneInfo.FindSystemTimeZoneById(timeZoneId);
            return TimeZoneInfo.ConvertTimeFromUtc(time, tzi); 
        } 
    }

Hope this will help you and save your time.

Enjoy !!!

Convert Json to Class in C#

Here it is a sample code to convert json data into Class object.

namespace JsonToClass
{
    class Program
    {
        static void Main(string[] args)
        {
            var jsonInput = "{ username:'myName',password:'myPass'}";
 
            var data = JsonConvert.DeserializeObject<demo>(jsonInput);
        }
    }
 
    class demo
    {
        public string username { get; set; }
        public string password { get; set; }
    }
}

Hope this will help you and save your time.

Enjoy !!!